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TPS65320QPWPRQ1 Datasheet(PDF) 21 Page - Texas Instruments |
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TPS65320QPWPRQ1 Datasheet(HTML) 21 Page - Texas Instruments |
21 / 34 page ![]() ( ) out in _ max out ripple in _ max o SW V V V I V L f ´ - = ´ ´ in _ max out out o min O IND in _ max SW V V V L I K V f - = ´ ´ ´ GND SW BOOT VIN RT/CLK SS Supply nRST FB1 EN2 3.3V COMP TPS65320-Q1 EN1 Power Pad VI = 3.6V to 40V LDO_OUT VIN_LDO FB2 C1 4.7 F R1 47k C2 3.3nF R4 27k R5 62k R6 20k C6 2.7nF C7 10 F C8(Optional) 5.4pF D1 5V R3 10k R2 53.6k C3 0.1 F L1 2.2 H C4 22 F C5 22 F TPS65320-Q1 www.ti.com SLVSAY9A – DECEMBER 2012 – REVISED APRIL 2013 Figure 23. TPS65320-Q1 Design Example With 2.2-MHz Switching Frequency Output Inductor Selection To calculate the minimum value of the output inductor, use Equation 20. The output capacitor filters the inductor ripple current. Therefore, choosing high inductor ripple currents impacts the selection of the output capacitor, because the output capacitor must have a ripple-current rating equal to or greater than the inductor ripple current. In general, the inductor ripple value is at the discretion of the designer; however, one can use the following guidelines. KIND is a coefficient that represents the amount of inductor ripple current relative to the maximum output current. For designs using low-ESR output capacitors such as ceramics, one can use a value as high as KIND = 0.3. When using higher-ESR output capacitors, KIND = 0.2 yields better results. In a wide-input voltage regulator, it is best to choose an inductor ripple current on the larger side. This allows the inductor to still have a measurable ripple current with the input voltage at its minimum. For this design example, use KIND = 0.3 and the minimum inductor value calculates to be 1.73 µH. For this design, the choice is a nearest standard value: 2.2 µH. For the output filter inductor, it is important not to exceed the rms-current and saturation-current ratings. One can find the rms and peak inductor currents from Equation 22 and Equation 23. The inductor ripple current is 0.71 A, and the rms current is 3.01 A. For this design, the rms inductor current is 3.01 A and the peak inductor current is 3.36 A. The chosen inductor is a Coilcraft MSS1038-103NLB. It has a saturation-current rating of 4.52 A and an rms-current rating of 4.05 A. As the equation set demonstrates, lower ripple current reduces the output ripple voltage of the regulator but requires a larger value of inductance. Selecting higher ripple currents increases the output ripple voltage of the regulator but allows for a lower inductance value. (20) (21) Copyright © 2012–2013, Texas Instruments Incorporated Submit Documentation Feedback 21 Product Folder Links: TPS65320-Q1 |
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